**MATH3271**

**FW03**

**Solutions
to term test 1 **

The**
**total number of marks on this paper is 60 but grades will be
calculated out of 50.

Note the following properties of periodic functions.

If f(x) is T-periodic then it is nT-periodic where n is a positive integer.

If f(x) and g(x) are both T-periodic then so is their sum, difference, product and quotient.

is independent of a.

1. (6 marks)

(a) What is the period of the function cos(x+p) + cos(3x)?

cos(x+p) = -cos(x) is 2p -periodic

cos(3x) is 2p/3 -periodic and hence 2p -periodic.

Therefore cos(x+p) + cos(3x) is 2p -periodic.

This function is even since cosine is an even function.

(b) What is the period of the function cos(2px)sin(5px)?

cos(2px) has period 1and hence is 2-periodic

sin(5px) has period 2/5 and hence is 2-periodic

Therefore cos(2px)sin(5px) is 2-periodic.

This function is odd since cosine is even and sine id odd.

2. (4 marks)

(a) Write down the appropriate boundary conditions for the heat equation for a bar of length L when one end is kept at 0 degrees while the other end is allowed to radiate.

Boundary condition for the end kept at zero degrees is u(x,0) = 0

Boundary condition for the radiating end is

(b) Explain briefly what is meant by the Gibbs phenomenon with regard to Fourier series.

A finite Fourier series overshoots a function near a singularity.

3. (9 marks) Suppose that
f(x) is a 2p-periodic function with Fourier coefficients a_{0},
a_{n} and b_{n}, n = 1, ¥.
If the function F(x) = f(x+p) has Fourier coefficients A_{0},
A_{n} and B_{n} n = 1, ¥,
show that A_{0} = a_{0}, A_{n} = (-1)^{n}a_{n}.

From the formula sheet

where we have made the substitution s = x+p and used the property of the integral of a periodic function stated above to justify the change of limits. Similarly

using the same substitution as above and the fact that

cos(np(s-p)/p)
= cos( nps/p -np)
= (-1)^{n} cos( nps/p)

4. (8 marks) Find the half-range sine expansion for cos(2px) for 0 < x < 1.

The half-range sine expansion is given by

where

Thus b_{2k} = 0 while

Note that when n = 2 the second term in the integral above is zero but this gives the same result.

5. (7 marks) Define completely the function f*(x) and G(x) in d'Alembert's solution of the one-dimensional wave equation for 0 < x < 1 with initial conditions

u(x, 0) = 2x + x^{2}

u_{t}(x, 0) =
cos(3px).

f* is the odd extension of
2x + x^{2} and must be periodic of period 2. Thus

f*(x) = 2x + x^{2 }if
0 < x <1; 2x - x^{2} if -1 < x < 0 and f*(x+2)
otherwise.

Similarly g*(x) = cos(3px) if 0 < x <1; cos(3px) if -1 < x < 0 and g*(x+2) otherwise.

Now taking a = 1 in the definition of G we have

and G(x) = G(x+2) otherwise.

6. (13 marks) Use separation of variables to derive the solution of the one-dimensional wave equation

subject to the boundary conditions u(0, t) = 0, u(p, t) = 0

and the initial conditions
u(x, 0) = 3 sin(2x), u_{t}(x, 0) = 5 sin(3x).

Give explicit expressions for the Fourier coefficients in the solution.

See the text for the derivation of the separated solution. Now for L = p

so that applying the initial conditions we have

Thus a_{n} = 0 if n ¹
2 while a_{2} = 3. Also

Thus b_{n} = 0 if n¹
3 while b_{3} = 5/3c giving u(x,t) = 3 cos(2ct) sin(2x)
+(5/3c) sin(3ct) sin(3x).

7. (13 marks) Use separation of variables to derive the solution of the two-dimensional heat equation

for a rectangular plate if the edges are kept at zero degrees and the initial temperature distribution is given by f(x, y) = 12 sin(2px/a)sin(4py/b), 0 < x < a, 0 < y < b.

See the text for the derivation of the separated solution

where

The initial condition gives

Thus A_{mn} = 0 unless
m = 2 and n = 4 when A_{24} = 12 giving

u(x, y, t) = 12 sin(2p
x/a) sin(4p
y/b) exp(-l_{24}^{2}
t)